Two metal plates each of area $A$ form a parallel plate capacitor with air in between the plates. The distance between the plates is $d$. $A$ metal plate of thickness $\frac{d}{2}$ and of same area $A$ is inserted between the plates to form two capacitors of capacitances $C_1$ and $C_2$ as shown in the figure. If the effective capacitance of the two capacitors is $C^{\prime}$ and the capacitance of the capacitor initially is $C$,then $\frac{C^{\prime}}{C}$ is

  • A
    $4$
  • B
    $2$
  • C
    $6$
  • D
    $1$

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If the distance between parallel plates of a capacitor is halved and the dielectric constant is doubled,then the capacitance:

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