Two mirrors,labeled LM for left mirror and RM | vedclass

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(C) Let the position of the person be $x = 0$. The right mirror $(RM)$ is at $x = 1 \, m$ and the left mirror $(LM)$ is at $x = -2 \, m$.The first ima

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(C) Let the position of the person be $x = 0$. The right mirror $(RM)$ is at $x = 1 \, m$ and the left mirror $(LM)$ is at $x = -2 \, m$.The first image $I_1$ in the right mirror $(RM)$ is formed by the person at $x = 0$. The distance of the person from $RM$ is $1 \, m$,so the image $I_1$ is formed $1 \, m$ behind $RM$,at $x = 2 \, m$.The second image $I_2$ in the right mirror $(RM)$ is formed by the reflection of the image of the person in the left mirror $(LM)$. The person is $2 \, m$ from $LM$,so the image $I_{LM}$ is formed $2 \, m$ behind $LM$,at $x = -4 \, m$. This image $I_{LM}$ acts as an object for the right mirror $(RM)$. The distance of $I_{LM}$ from $RM$ is $1 \, m + 2 \, m + 2 \, m = 5 \, m$. Thus,the second image $I_2$ is formed $5 \, m$ behind $RM$,at $x = 1 \, m + 5 \, m = 6 \, m$.The distance of the second image $I_2$ from the person (at $x = 0$) is $6 \, m - 0 = 6 \, m$.

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