Two molecules of acetyl CoA form . . . . . . | vedclass

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(B) The Krebs cycle (also known as the Citric Acid Cycle) processes one molecule of acetyl CoA at a time.For one molecule of acetyl CoA,the products g

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$6 NADH + 2 FADH_2 + 2 GTP$

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(B) The Krebs cycle (also known as the Citric Acid Cycle) processes one molecule of acetyl CoA at a time.For one molecule of acetyl CoA,the products generated are $3 NADH$,$1 FADH_2$,and $1 GTP$ (or $ATP$).Since the question asks for the products from two molecules of acetyl CoA,we multiply the products of one cycle by $2$.Therefore,$2 	imes (3 NADH + 1 FADH_2 + 1 GTP) = 6 NADH + 2 FADH_2 + 2 GTP$.

Two molecules of acetyl CoA form . . . . . . after entering the Krebs cycle.

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