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(A) The molar specific heat at constant volume for a mixture is given by the formula: $C_{V,mix} = \frac{n_1 C_{V,1} + n_2 C_{V,2}}{n_1 + n_2}$.For a

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$\frac{9}{4} R$

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(A) The molar specific heat at constant volume for a mixture is given by the formula: $C_{V,mix} = \frac{n_1 C_{V,1} + n_2 C_{V,2}}{n_1 + n_2}$.For a monoatomic gas,$C_{V,1} = \frac{3}{2} R$ and $n_1 = 2$.For a diatomic gas,$C_{V,2} = \frac{5}{2} R$ and $n_2 = 6$.Substituting these values into the formula:$C_{V,mix} = \frac{2 	imes (\frac{3}{2} R) + 6 	imes (\frac{5}{2} R)}{2 + 6}$$C_{V,mix} = \frac{3R + 15R}{8}$$C_{V,mix} = \frac{18R}{8} = \frac{9}{4} R$.

Two moles of a monoatomic gas are mixed with six moles of a diatomic gas. The molar specific heat of the mixture at constant volume is:

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