Two moving coil galvanometers A and B having | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The current sensitivity $(I_s)$ of a moving coil galvanometer is given by the formula: $I_s = \frac{NBA}{k}$,where $N$ is the number of turns,$B$

Vedclass · Accepted Answer

$3: 16$

Vedclass · Answer

(A) The current sensitivity $(I_s)$ of a moving coil galvanometer is given by the formula: $I_s = \frac{NBA}{k}$,where $N$ is the number of turns,$B$ is the magnetic field,$A$ is the area of the coil,and $k$ is the torsional constant of the spring.Since the springs are identical,$k_A = k_B = k$.The ratio of current sensitivities is $\frac{I_{sA}}{I_{sB}} = \frac{N_A B_A A_A}{N_B B_B A_B}$.Given values:$N_A = 36, B_A = 0.25 \ T, A_A = 2.4 	imes 10^{-3} \ m^2$$N_B = 48, B_B = 0.5 \ T, A_B = 4.8 	imes 10^{-3} \ m^2$Substituting these values:$\frac{I_{sA}}{I_{sB}} = \frac{36 	imes 0.25 	imes 2.4 	imes 10^{-3}}{48 	imes 0.5 	imes 4.8 	imes 10^{-3}}$$\frac{I_{sA}}{I_{sB}} = \left(\frac{36}{48}ight) 	imes \left(\frac{0.25}{0.5}ight) 	imes \left(\frac{2.4}{4.8}ight)$$\frac{I_{sA}}{I_{sB}} = \left(\frac{3}{4}ight) 	imes \left(\frac{1}{2}ight) 	imes \left(\frac{1}{2}ight) = \frac{3}{16}$.Thus,the ratio is $3: 16$.

Similar Questions

The deflection in a galvanometer falls to $\left(\frac{1}{4}\right)^{th}$ of its initial value when it is shunted by a resistor of $3 \Omega$. If an additional shunt of $2 \Omega$ is connected in parallel to the earlier shunt,the deflection in the galvanometer falls to:

The graph which represents the relation between the total resistance $R$ of a multi-range moving coil voltmeter and its full-scale deflection $V$ is

The resistance of a galvanometer is $90\, \Omega$. If only $10\%$ of the main current is to flow through the galvanometer,how should a resistor be connected and what should be its value?

$A$ galvanometer of resistance '$G$' is shunted by a resistance of '$S$' ohm. To keep the main current in the circuit unchanged,the resistance to be put in series with the galvanometer is:

Current sensitivities of two galvanometers $G_1$ and $G_2$ of resistances $100 \ \Omega$ and $50 \ \Omega$ are $10^8 \ \text{div/A}$ and $0.5 \times 10^5 \ \text{div/A}$ respectively. The galvanometer in which the voltage sensitivity is more is

Vedclass Test Series

Exam Paper Generator

Online Exam Module