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(C) Let the total population be $100$.Given:$n(A) = 25$$n(B) = 20$$n(A \cap B) = 8$Now, calculate the number of people who read only one newspaper:$n(

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$13.9$

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(C) Let the total population be $100$.Given:$n(A) = 25$$n(B) = 20$$n(A \cap B) = 8$Now, calculate the number of people who read only one newspaper:$n(A 	ext{ only}) = n(A) - n(A \cap B) = 25 - 8 = 17$$n(B 	ext{ only}) = n(B) - n(A \cap B) = 20 - 8 = 12$Percentage of population looking into advertisements:$= (30\% 	ext{ of } 17) + (40\% 	ext{ of } 12) + (50\% 	ext{ of } 8)$$= (0.30 	imes 17) + (0.40 	imes 12) + (0.50 	imes 8)$$= 5.1 + 4.8 + 4.0$$= 13.9$Thus, $13.9\%$ of the population looks into advertisements.

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