Two numbers are 50 % and 80 % less than a thi | vedclass

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(C) Let the third number be $100$.The first number is $50 \%$ less than the third number,so it is $100 - 50 = 50$.The second number is $80 \%$ less th

Vedclass · Accepted Answer

$150$ per cent

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(C) Let the third number be $100$.The first number is $50 \%$ less than the third number,so it is $100 - 50 = 50$.The second number is $80 \%$ less than the third number,so it is $100 - 80 = 20$.We need to increase the second number $(20)$ to make it equal to the first number $(50)$.The required increase is $50 - 20 = 30$.The percentage increase required is $\frac{	ext{Increase}}{	ext{Original Number}} 	imes 100 = \frac{30}{20} 	imes 100 = 1.5 	imes 100 = 150 \%$.

Two numbers are $50 \%$ and $80 \%$ less than a third number. By what percentage must the second number be increased to make it equal to the first number?

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