Two numbers are in the ratio 3: 5. If each nu | vedclass

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(A) Let the two numbers be $3x$ and $5x$.According to the problem,if each number is increased by $10$,the new ratio is $5: 7$.So,$\frac{3x + 10}{5x +

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$15, 25$

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(A) Let the two numbers be $3x$ and $5x$.According to the problem,if each number is increased by $10$,the new ratio is $5: 7$.So,$\frac{3x + 10}{5x + 10} = \frac{5}{7}$.Cross-multiplying,we get: $7(3x + 10) = 5(5x + 10)$.$21x + 70 = 25x + 50$.Rearranging the terms: $70 - 50 = 25x - 21x$.$20 = 4x$,which gives $x = 5$.The numbers are $3x = 3 	imes 5 = 15$ and $5x = 5 	imes 5 = 25$.Therefore,the numbers are $15$ and $25$.

Two numbers are in the ratio $3: 5$. If each number is increased by $10$,the ratio becomes $5: 7$. The numbers are:

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