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(C) Let the two numbers be $4x$ and $7x$.According to the problem,if each number is increased by $4$,the ratio becomes $3:5$.So,the equation is: $\fra

Vedclass · Accepted Answer

$56$

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(C) Let the two numbers be $4x$ and $7x$.According to the problem,if each number is increased by $4$,the ratio becomes $3:5$.So,the equation is: $\frac{4x + 4}{7x + 4} = \frac{3}{5}$.By cross-multiplying,we get: $5(4x + 4) = 3(7x + 4)$.$20x + 20 = 21x + 12$.Rearranging the terms to solve for $x$: $20 - 12 = 21x - 20x$.$x = 8$.The two numbers are $4 	imes 8 = 32$ and $7 	imes 8 = 56$.The larger number is $56$.

Two numbers are such that the ratio between them is $4:7$. If each is increased by $4$,the ratio becomes $3:5$. The larger number is:

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