Two numbers differ by 5. If their product is | vedclass

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(C) Let the two numbers be $x$ and $y$ such that $x > y$.Given that the difference between the numbers is $5$,so $x - y = 5$.Given that their product

Vedclass · Accepted Answer

$37$

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(C) Let the two numbers be $x$ and $y$ such that $x > y$.Given that the difference between the numbers is $5$,so $x - y = 5$.Given that their product is $336$,so $x y = 336$.We use the algebraic identity $(x + y)^2 = (x - y)^2 + 4xy$.Substituting the given values:$(x + y)^2 = (5)^2 + 4(336)$$(x + y)^2 = 25 + 1344$$(x + y)^2 = 1369$Taking the square root on both sides,we get $x + y = \sqrt{1369} = 37$.Thus,the sum of the two numbers is $37$.

Two numbers differ by $5$. If their product is $336$,then the sum of the two numbers is

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