Two objects of masses 100 , g and 200 , g are | vedclass

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(D) Mass of the first object,$m_1 = 100 \, g = 0.1 \, kg$.Mass of the second object,$m_2 = 200 \, g = 0.2 \, kg$.Velocity of $m_1$ before collision,$u

Vedclass · Accepted Answer

$1.165$

Vedclass · Answer

(D) Mass of the first object,$m_1 = 100 \, g = 0.1 \, kg$.Mass of the second object,$m_2 = 200 \, g = 0.2 \, kg$.Velocity of $m_1$ before collision,$u_1 = 2 \, m/s$.Velocity of $m_2$ before collision,$u_2 = 1 \, m/s$.Velocity of $m_1$ after collision,$v_1 = 1.67 \, m/s$.Let the velocity of $m_2$ after collision be $v_2$.According to the law of conservation of momentum:Total momentum before collision = Total momentum after collision$m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$$(0.1 	imes 2) + (0.2 	imes 1) = (0.1 	imes 1.67) + (0.2 	imes v_2)$$0.2 + 0.2 = 0.167 + 0.2 v_2$$0.4 = 0.167 + 0.2 v_2$$0.2 v_2 = 0.4 - 0.167$$0.2 v_2 = 0.233$$v_2 = 0.233 / 0.2 = 1.165 \, m/s$.Thus,the velocity of the second object after the collision is $1.165 \, m/s$.

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