Two parallel pillars are 11 , km away from an | vedclass

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(A) The limit of resolution of the human eye is approximately $1' = (1/60)^\circ$. For the pillars to be seen as distinct, the angular separation $	h

Vedclass · Accepted Answer

$3.2$

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(A) The limit of resolution of the human eye is approximately $1' = (1/60)^\circ$. For the pillars to be seen as distinct, the angular separation $	heta$ between them must be greater than this limit.Given distance $x = 11 \, km = 11 	imes 10^3 \, m$.The angular resolution $	heta = (1/60)^\circ = (1/60) 	imes (\pi/180) \, 	ext{radians}$.The relationship between the distance $d$ between the pillars, the distance $x$ from the observer, and the angle $	heta$ is given by $	heta = d/x$ (for small angles).Therefore, $d = x 	imes 	heta = (11 	imes 10^3) 	imes (1/60) 	imes (\pi/180)$.$d = (11000 	imes 3.14) / (60 	imes 180) \approx 34540 / 10800 \approx 3.198 \, m$.Rounding to the nearest value, $d \approx 3.2 \, m$.

Two parallel pillars are $11 \, km$ away from an observer. The minimum distance between the pillars so that they can be seen separately will be.....$m$

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