Two particles having mass M and m are moving | vedclass

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Question

(A) The angular velocity $\omega$ of a particle moving in a circular path is related to its time period $T$ by the formula: $\omega = \frac{2\pi}{T}$.

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(A) The angular velocity $\omega$ of a particle moving in a circular path is related to its time period $T$ by the formula: $\omega = \frac{2\pi}{T}$.Since the time period $T$ is the same for both particles $(T_1 = T_2 = T)$,their angular velocities are:$\omega_1 = \frac{2\pi}{T_1}$ and $\omega_2 = \frac{2\pi}{T_2}$.Therefore,$\omega_1 = \omega_2$.The ratio of the angular velocity of the first particle to the second particle is $\frac{\omega_1}{\omega_2} = \frac{1}{1}$.

Two particles having mass $M$ and $m$ are moving in a circular path with radius $R$ and $r$ respectively. The time period for both the particles is same. The ratio of angular velocity of the first particle to the second particle will be

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