Two particles having mass M and m are moving | vedclass

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(A) The angular velocity $\omega$ of a particle moving in a circular path is related to its time period $T$ by the formula $\omega = \frac{2\pi}{T}$.G

Vedclass · Accepted Answer

$1$

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(A) The angular velocity $\omega$ of a particle moving in a circular path is related to its time period $T$ by the formula $\omega = \frac{2\pi}{T}$.Given that the time period $T$ is the same for both particles, let $T_1 = T_2 = T$.For the first particle, the angular velocity is $\omega_1 = \frac{2\pi}{T_1} = \frac{2\pi}{T}$.For the second particle, the angular velocity is $\omega_2 = \frac{2\pi}{T_2} = \frac{2\pi}{T}$.The ratio of the angular velocity of the first particle to that of the second particle is $\frac{\omega_1}{\omega_2} = \frac{2\pi/T}{2\pi/T} = 1$.Therefore, the ratio is $1$.

Two particles having mass $M$ and $m$ are moving in a circular path with radius $R$ and $r$ respectively. The time period for both the particles is same. The ratio of angular velocity of the first particle to that of the second particle will be

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