Two plane mirrors are inclined to one another | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the angle of incidence on mirror $M_1$ be $i$. The angle of reflection is also $i$.The angle between the reflected ray and the mirror $M_1$ is

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(C) Let the angle of incidence on mirror $M_1$ be $i$. The angle of reflection is also $i$.The angle between the reflected ray and the mirror $M_1$ is $(90^o - i)$.In the triangle formed by the two mirrors and the reflected ray,the sum of the interior angles is $180^o$.The angles are $60^o$,$(90^o - i)$,and the angle of incidence on mirror $M_2$.From the figure,the reflected ray from $M_1$ strikes $M_2$ such that the ray reflected from $M_2$ is parallel to $M_1$. Thus,the angle of incidence on $M_2$ is $30^o$.Therefore,$60^o + (90^o - i) + 30^o = 180^o$.$180^o - i = 180^o$.$i = 30^o$.

Two plane mirrors are inclined to one another at an angle of $60^o$. $A$ ray is incident on mirror $M_1$ at an angle $i$. The reflected ray from mirror $M_1$ is shown in the figure. The angle of incidence $i$ is (in $^o$)

Similar Questions

$A$ mirror is placed at a distance of $60 \ m$ from the base of a tower. The angle between the top of the tower and the top of its image is $90^o$. Find the height of the tower in $m$.

The angle made by the incident ray of light with the reflecting surface is called:

The focal length of a plane mirror is .......

$A$ boy of height $1.5\, m$ with his eye level at $1.4\, m$ stands before a plane mirror of length $0.75\, m$ fixed on the wall. The height of the lower edge of the mirror above the floor is $0.8\, m$. Then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module