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(C) Let $d = 10 \, cm = 0.1 \, m$ be the distance between the mirrors and $L = 20 \, m$ be the length of the mirrors.After each reflection,the ray cov

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$150$

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(C) Let $d = 10 \, cm = 0.1 \, m$ be the distance between the mirrors and $L = 20 \, m$ be the length of the mirrors.After each reflection,the ray covers a horizontal distance $x$ along the mirror.From the geometry of the path,we have $	an 53^{\circ} = \frac{x}{d}$.Given $	an 53^{\circ} = \frac{4}{3}$,we get $x = d 	an 53^{\circ} = 0.1 	imes \frac{4}{3} \, m = \frac{0.4}{3} \, m$.The total number of reflections $n$ is given by the ratio of the total length $L$ to the horizontal distance covered per reflection $x$.$n = \frac{L}{x} = \frac{20}{0.4 / 3} = \frac{20 	imes 3}{0.4} = \frac{60}{0.4} = 150$.Thus,the light undergoes $150$ reflections.

Two plane mirrors $M_1$ and $M_2$ have a length of $20 \, m$ each and are $10 \, cm$ apart. $A$ ray of light is incident on one end of mirror $M_2$ at an angle of $53^{\circ}$. The number of reflections the light undergoes before reaching the other end is

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