Two plane mirrors are parallel to each other | vedclass

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(C) Let the distance between the two mirrors $M_1$ and $M_2$ be $d = 15 \ cm$. The object $O$ is at a distance $x = 5 \ cm$ from $M_2$ and $y = 10 \ c

Vedclass · Accepted Answer

$5, 25, 35$

Vedclass · Answer

(C) Let the distance between the two mirrors $M_1$ and $M_2$ be $d = 15 \ cm$. The object $O$ is at a distance $x = 5 \ cm$ from $M_2$ and $y = 10 \ cm$ from $M_1$.$1$. The first image formed by $M_2$ (let's call it $I_{2,1}$) is at a distance of $5 \ cm$ behind $M_2$.$2$. The first image formed by $M_1$ (let's call it $I_{1,1}$) is at a distance of $10 \ cm$ behind $M_1$. This image acts as an object for $M_2$. The distance of $I_{1,1}$ from $M_2$ is $15 \ cm$ (distance between mirrors) $+ 10 \ cm = 25 \ cm$. Thus,the second image formed by $M_2$ (let's call it $I_{2,2}$) is at a distance of $25 \ cm$ behind $M_2$.$3$. The next image formed by $M_1$ (let's call it $I_{1,2}$) is formed by the reflection of $I_{2,1}$ in $M_1$. The distance of $I_{2,1}$ from $M_1$ is $15 \ cm + 5 \ cm = 20 \ cm$. So,$I_{1,2}$ is $20 \ cm$ behind $M_1$. This image acts as an object for $M_2$. The distance of $I_{1,2}$ from $M_2$ is $15 \ cm + 20 \ cm = 35 \ cm$. Thus,the third image formed by $M_2$ (let's call it $I_{2,3}$) is at a distance of $35 \ cm$ behind $M_2$.Therefore,the distances of the first three images from $M_2$ are $5 \ cm, 25 \ cm, 35 \ cm$.

Two plane mirrors are parallel to each other and an object $O$ is placed between them. Then the distance of the first three images from the mirror $M_2$ will be (in $cm$):

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