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(A) Let the two mirrors be $M_1$ and $M_2$ separated by distance $L$. The object $O$ is at distance $x = L/3$ from $M_1$ and $y = 2L/3$ from $M_2$.Ima

Vedclass · Accepted Answer

$\frac{3L}{2}$

Vedclass · Answer

(A) Let the two mirrors be $M_1$ and $M_2$ separated by distance $L$. The object $O$ is at distance $x = L/3$ from $M_1$ and $y = 2L/3$ from $M_2$.Images formed by $M_1$ are at distances $x, 2L+x, 4L+x, \dots$ from $M_1$,i.e.,$L/3, 7L/3, 13L/3, \dots$Images formed by $M_2$ are at distances $y, 2L+y, 4L+y, \dots$ from $M_2$,i.e.,$2L/3, 8L/3, 14L/3, \dots$Converting all positions relative to $M_1$: Positions from $M_1$: $L/3, 7L/3, 13L/3, \dots$ and $(L - 2L/3) = L/3$ (reflected),$(L + 2L/3) = 5L/3, (3L + 2L/3) = 11L/3, \dots$Sorted positions from $M_1$: $L/3, 5L/3, 7L/3, 11L/3, 13L/3, 17L/3, \dots$The gaps between consecutive images are: $4L/3, 2L/3, 4L/3, 2L/3, 4L/3, \dots$Since the possible distances between any two images are multiples of $2L/3$ (specifically $2L/3, 4L/3, 6L/3=2L, 8L/3, \dots$),the value $\frac{3L}{2}$ is not possible.

Two plane mirrors are placed parallel to each other at a distance $L$ apart. $A$ point object $O$ is placed between them at a distance $L/3$ from one mirror. Both mirrors form multiple images. The distance between any two images cannot be:

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