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(C) According to Coulomb's law,the force of repulsion between two positive ions each of charge $q$ separated by a distance $d$ is given by:$F = \frac{

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$\sqrt{\frac{4\pi \varepsilon_0 F d^2}{e^2}}$

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(C) According to Coulomb's law,the force of repulsion between two positive ions each of charge $q$ separated by a distance $d$ is given by:$F = \frac{1}{4 \pi \varepsilon_{0}} \frac{q^2}{d^2}$Rearranging for $q^2$:$q^2 = 4 \pi \varepsilon_{0} F d^2$Taking the square root:$q = \sqrt{4 \pi \varepsilon_{0} F d^2} \quad ...(i)$Since the charge on an ion is due to missing electrons,we use the quantization of charge formula:$q = ne$where $n$ is the number of missing electrons and $e$ is the elementary charge.Substituting $q$ from equation $(i)$:$ne = \sqrt{4 \pi \varepsilon_{0} F d^2}$$n = \frac{\sqrt{4 \pi \varepsilon_{0} F d^2}}{e}$$n = \sqrt{\frac{4 \pi \varepsilon_{0} F d^2}{e^2}}$

Two positive ions,each carrying a charge $q,$ are separated by a distance $d.$ If $F$ is the force of repulsion between the ions,the number of electrons missing from each ion will be ($e$ being the charge on an electron).

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