Two rails are represented by the equations $x+2y-4=0$ and $2x+4y-12=0$. Represent this situation geometrically.

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(N/A) To represent the equations geometrically,we find two solutions for each equation.
For the equation $x+2y-4=0$:
$x$$0$$4$
$y = \frac{4-x}{2}$$2$$0$

We plot the points $R(0, 2)$ and $S(4, 0)$ to get the line representing $x+2y-4=0$.
For the equation $2x+4y-12=0$:
$x$$0$$6$
$y = \frac{12-2x}{4}$$3$$0$

We plot the points $P(0, 3)$ and $Q(6, 0)$ to get the line representing $2x+4y-12=0$.
Observing the graph,we see that the two lines do not intersect anywhere,which means they are parallel to each other.

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