Two resistors of 3 Omega and 6 Omega are conn | vedclass

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(C) When resistors are connected in parallel,the equivalent resistance $R$ is given by the formula: $\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2}$.Give

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$2 \Omega$

Vedclass · Answer

(C) When resistors are connected in parallel,the equivalent resistance $R$ is given by the formula: $\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2}$.Given $R_1 = 3 \Omega$ and $R_2 = 6 \Omega$.Substituting the values: $\frac{1}{R} = \frac{1}{3} + \frac{1}{6}$.Finding a common denominator: $\frac{1}{R} = \frac{2}{6} + \frac{1}{6} = \frac{3}{6}$.Therefore,$\frac{1}{R} = \frac{1}{2}$.Thus,$R = 2 \Omega$.

Two resistors of $3 \Omega$ and $6 \Omega$ are connected in parallel. The equivalent resistance $R$ is:

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