Two rods,one of aluminium and the other of st | vedclass

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(C) The change in length of a rod due to thermal expansion is given by $\Delta L = L \alpha \Delta T$.Given that the change in length for both rods is

Vedclass · Accepted Answer

$\frac{\alpha_2}{(\alpha_1+\alpha_2)}$

Vedclass · Answer

(C) The change in length of a rod due to thermal expansion is given by $\Delta L = L \alpha \Delta T$.Given that the change in length for both rods is the same,we have $\Delta L_1 = \Delta L_2$.Substituting the formula,we get $L_1 \alpha_1 t = L_2 \alpha_2 t$.Canceling $t$ from both sides,we get $L_1 \alpha_1 = L_2 \alpha_2$,which implies $\frac{L_1}{L_2} = \frac{\alpha_2}{\alpha_1}$.To find the ratio $\frac{L_1}{L_1+L_2}$,we use the property of ratios: if $\frac{a}{b} = \frac{c}{d}$,then $\frac{a}{a+b} = \frac{c}{c+d}$.Applying this to our equation,we get $\frac{L_1}{L_1+L_2} = \frac{\alpha_2}{\alpha_1+\alpha_2}$.

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