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(C) galvanometer is converted into an ammeter by connecting a small shunt resistance $S$ in parallel with it.For a galvanometer with resistance $G$ an

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(C) galvanometer is converted into an ammeter by connecting a small shunt resistance $S$ in parallel with it.For a galvanometer with resistance $G$ and full-scale deflection current $i_g$,if it is to measure a maximum current $i$,the shunt resistance $S$ is given by:$S = \frac{i_g G}{i - i_g}$From this formula,we can see that $S \propto \frac{1}{i - i_g}$.Since an ammeter is designed to measure a larger current $(i_{ammeter})$ compared to a milliammeter $(i_{milliammeter})$,the denominator $(i - i_g)$ will be larger for the ammeter.Therefore,the shunt resistance $S$ required for the ammeter will be less than the shunt resistance required for the milliammeter.Thus,the shunt resistance of the ammeter is less than that of the milliammeter.

Two similar galvanometers are converted into an ammeter and a milliammeter. The shunt resistance of the ammeter as compared to the shunt resistance of the milliammeter will be

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