Two simple pendulums of equal length cross each other at the mean position. What is their phase difference?

(C) When two pendulums of equal length cross each other at the mean position,they are moving in opposite directions.
If one pendulum is at the mean position moving towards the right,its displacement is $x = A \sin(\omega t)$,which implies it is at phase $\phi_1 = 0$ or $\pi$.
If the other pendulum is crossing the same mean position moving towards the left,its motion is represented by $x = A \sin(\omega t + \pi)$.
The phase difference between the two motions is $\Delta \phi = \pi - 0 = \pi \text{ rad}$ or $180^{\circ}$.