Two sinusoidal voltages of the same frequency | vedclass

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(B) From the graph,the time period $T$ (time taken to complete one full cycle) for wave $M$ is $0.4 \, s$.Therefore,the frequency $f = \frac{1}{T} = \

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$2.5 	o -\pi/2$

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(B) From the graph,the time period $T$ (time taken to complete one full cycle) for wave $M$ is $0.4 \, s$.Therefore,the frequency $f = \frac{1}{T} = \frac{1}{0.4} = 2.5 \, Hz$.Wave $M$ starts at $t=0$ with a value of $0$,while wave $N$ reaches the same point at $t=0.1 \, s$.The time shift $\Delta t$ between the two waves is $0.1 \, s$.The phase difference $\Delta \phi$ is given by $\Delta \phi = \frac{2\pi}{T} 	imes \Delta t = \frac{2\pi}{0.4} 	imes 0.1 = \frac{2\pi}{4} = \frac{\pi}{2}$.Since wave $N$ lags behind wave $M$,the phase lead of $N$ over $M$ is $-\frac{\pi}{2}$ radians.

Two sinusoidal voltages of the same frequency are shown in the diagram. What is the frequency and the phase relationship between the voltages? (Frequency in $Hz$ $\to$ Phase lead of $N$ over $M$ in radian)

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