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(A) The formula for fringe width (fringe separation) in Young's double-slit experiment is given by $\beta = \frac{D \lambda}{d}$.Given:Distance betwee

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$5	imes10^{-4}\, m$

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(A) The formula for fringe width (fringe separation) in Young's double-slit experiment is given by $\beta = \frac{D \lambda}{d}$.Given:Distance between slits,$d = 1\, mm = 1 	imes 10^{-3}\, m$.Distance of the screen,$D = 1\, m$.Wavelength of light,$\lambda = 500\, nm = 500 	imes 10^{-9}\, m = 5 	imes 10^{-7}\, m$.Substituting these values into the formula:$\beta = \frac{1 	imes 5 	imes 10^{-7}}{1 	imes 10^{-3}} = 5 	imes 10^{-4}\, m$.Thus,the fringe separation is $5 	imes 10^{-4}\, m$.

Two slits are made $1\, mm$ apart and the screen is placed $1\, m$ away. The fringe separation when monochromatic light of wavelength $500\, nm$ is used is

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