Two small spheres,each having an equal positi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the absence of gravity,the only force acting on each sphere is the electrostatic repulsive force exerted by the other sphere.Since the spheres

Vedclass · Accepted Answer

$\frac{Q^2}{16 \pi \varepsilon_0 L^2}$

Vedclass · Answer

(A) In the absence of gravity,the only force acting on each sphere is the electrostatic repulsive force exerted by the other sphere.Since the spheres are held in a horizontal position,the distance between the two spheres is $2L$.According to Coulomb's law,the electrostatic force $F$ between the two charges is given by:$F = \frac{1}{4 \pi \varepsilon_0} \frac{Q \cdot Q}{(2L)^2} = \frac{1}{4 \pi \varepsilon_0} \frac{Q^2}{4L^2} = \frac{Q^2}{16 \pi \varepsilon_0 L^2}$.Since the spheres are in equilibrium,the tension $T$ in each string must balance this electrostatic force.Therefore,$T = F = \frac{Q^2}{16 \pi \varepsilon_0 L^2}$.

Similar Questions

Which is the most important center for lymph formation?

If pairs of straight lines $x^2-2 p x y-y^2=0$ and $x^2-2 q x y-y^2=0$ be such that each pair bisects the angle between the other pair,then

In humans,which disorder is caused due to the absence of one of the $X$ chromosomes,i.e.,$45$ chromosomes with $XO$ genotype?

Identify $A$ and $B$ in the following reaction:
$C_2H_5Cl \xrightarrow{A} C_2H_5OH \xleftarrow{B} C_2H_5Cl$

Given that:
$2C_{(s)} + 2O_{2(g)} \to 2CO_{2(g)}; \Delta H = -787 \ kJ$
$H_{2(g)} + 1/2 O_{2(g)} \to H_2O_{(l)}; \Delta H = -286 \ kJ$
$C_2H_{2(g)} + 2.5 O_{2(g)} \to 2CO_{2(g)} + H_2O_{(l)}; \Delta H = -1301 \ kJ$
Calculate the heat of formation of acetylene $(C_2H_{2(g)})$ in $kJ$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module