Two solids P and Q float in water. It is obse | vedclass

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(B) According to the law of floatation,for a body floating in equilibrium,the weight of the body is equal to the buoyant force (weight of the displace

Vedclass · Accepted Answer

$\frac{3}{4}$

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(B) According to the law of floatation,for a body floating in equilibrium,the weight of the body is equal to the buoyant force (weight of the displaced liquid).Let $V$ be the total volume of each solid,$ho_P$ and $ho_Q$ be their densities,and $ho_w$ be the density of water.For solid $P$: $V ho_P g = (V/2) ho_w g \Rightarrow ho_P = \frac{1}{2} ho_w$.For solid $Q$: $V ho_Q g = (2V/3) ho_w g \Rightarrow ho_Q = \frac{2}{3} ho_w$.The ratio of densities is $\frac{ho_P}{ho_Q} = \frac{\frac{1}{2} ho_w}{\frac{2}{3} ho_w} = \frac{1}{2} 	imes \frac{3}{2} = \frac{3}{4}$.

Two solids $P$ and $Q$ float in water. It is observed that $P$ floats with half of its volume immersed and $Q$ floats with $\frac{2}{3}$ of its volume immersed. The ratio of densities of $P$ and $Q$ is

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