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(B) For stone $A$ dropped from $h_1 = 100 \, m$:Using the equation $v^2 - u^2 = 2gh$,where initial velocity $u = 0$:$v_A^2 = 2 	imes 10 	imes 100 =

Vedclass · Accepted Answer

No,stone $A$ will have higher velocity.

Vedclass · Answer

(B) For stone $A$ dropped from $h_1 = 100 \, m$:Using the equation $v^2 - u^2 = 2gh$,where initial velocity $u = 0$:$v_A^2 = 2 	imes 10 	imes 100 = 2000$$v_A = \sqrt{2000} \approx 44.72 \, m s^{-1}$.For stone $B$ dropped from $h_2 = 50 \, m$:Using the equation $v^2 - u^2 = 2gh$,where initial velocity $u = 0$:$v_B^2 = 2 	imes 10 	imes 50 = 1000$$v_B = \sqrt{1000} \approx 31.62 \, m s^{-1}$.Since $v_A 
eq v_B$,the stones will not have equal velocities upon reaching the ground. Stone $A$ will have a higher velocity.

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