Two students,Anil and Ashima,appeared in an examination. The probability that Anil will qualify the examination is $0.05$ and that Ashima will qualify the examination is $0.10$. The probability that both will qualify the examination is $0.02$. Find the probability that at least one of them will not qualify the examination.
- A$0.98$
- B$0.95$
- C$0.90$
- D$0.87$
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Similar Questions
$A$ bag contains $9$ discs of which $4$ are red,$3$ are blue and $2$ are yellow. The discs are similar in shape and size. $A$ disc is drawn at random from the bag. Calculate the probability that it will be red. (in $/9$)
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View SolutionTwo coins (a one rupee coin and a two rupee coin) are tossed once. Find the sample space.
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View SolutionWhich of the following cannot be a valid assignment of probabilities for outcomes of sample space $S = \{\omega_{1}, \omega_{2}, \omega_{3}, \omega_{4}, \omega_{5}, \omega_{6}, \omega_{7}\}$?
Outcome Probability $\omega_{1}$ $\frac{1}{14}$ $\omega_{2}$ $\frac{2}{14}$ $\omega_{3}$ $\frac{3}{14}$ $\omega_{4}$ $\frac{4}{14}$ $\omega_{5}$ $\frac{5}{14}$ $\omega_{6}$ $\frac{6}{14}$ $\omega_{7}$ $\frac{15}{14}$
| Outcome | Probability |
| $\omega_{1}$ | $\frac{1}{14}$ |
| $\omega_{2}$ | $\frac{2}{14}$ |
| $\omega_{3}$ | $\frac{3}{14}$ |
| $\omega_{4}$ | $\frac{4}{14}$ |
| $\omega_{5}$ | $\frac{5}{14}$ |
| $\omega_{6}$ | $\frac{6}{14}$ |
| $\omega_{7}$ | $\frac{15}{14}$ |
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View SolutionFrom $10,000$ lottery tickets numbered from $1$ to $10,000$,one ticket is drawn at random. What is the probability that the number marked on the drawn ticket is divisible by $20$?
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View SolutionThe probability of obtaining an even prime number on each die,when a pair of dice is rolled,is . . . . . . .
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