Two substances A and B of equal mass m are he | vedclass

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(C) The rate of heat supply is constant for both substances,given as $P = 6 \, cal \, s^{-1}$.For a substance,the heat absorbed during the phase chang

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$8/5$

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(C) The rate of heat supply is constant for both substances,given as $P = 6 \, cal \, s^{-1}$.For a substance,the heat absorbed during the phase change (fusion) is given by $H = P 	imes \Delta t$,where $\Delta t$ is the time interval during which the temperature remains constant (the horizontal part of the graph).For substance $A$,the temperature remains constant from $t = 2 \, s$ to $t = 6 \, s$. Thus,the time interval for fusion is $\Delta t_A = 6 - 2 = 4 \, s$.The heat absorbed by $A$ is $H_A = P 	imes \Delta t_A = 6 	imes 4 = 24 \, cal$.For substance $B$,the temperature remains constant from $t = 4 \, s$ to $t = 6.5 \, s$ (as seen from the graph,the horizontal section ends between $6$ and $7$,specifically at $6.5$). Thus,the time interval for fusion is $\Delta t_B = 6.5 - 4 = 2.5 \, s$.The heat absorbed by $B$ is $H_B = P 	imes \Delta t_B = 6 	imes 2.5 = 15 \, cal$.The ratio of heat absorbed is $\frac{H_A}{H_B} = \frac{P 	imes \Delta t_A}{P 	imes \Delta t_B} = \frac{4}{2.5} = \frac{40}{25} = \frac{8}{5}$.

Column-$I$	Column-$II$
$(a)$ Latent heat of vaporization $L_V$	$(i)$ $22.6 \times 10^5 \, J/kg$
$(b)$ Latent heat of fusion $L_f$	$(ii)$ $33.3 \times 10^5 \, J/kg$
	$(iii)$ $3.33 \times 10^5 \, J/kg$

Two substances $A$ and $B$ of equal mass $m$ are heated at a uniform rate of $6 \, cal \, s^{-1}$ under similar conditions. $A$ graph between temperature and time is shown in the figure. The ratio of heat absorbed $H_A/H_B$ by them for complete fusion is

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