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(C) The rate of heat supply is constant for both substances,given by $P = \frac{dQ}{dt} = 6 \, cal \, s^{-1}$.For substance $A$,the fusion process occ

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$8/5$

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(C) The rate of heat supply is constant for both substances,given by $P = \frac{dQ}{dt} = 6 \, cal \, s^{-1}$.For substance $A$,the fusion process occurs at a constant temperature where the time taken is $\Delta t_A = 6 - 2 = 4 \, s$.Thus,the heat absorbed for fusion is $H_A = P 	imes \Delta t_A = 6 	imes 4 = 24 \, cal$.For substance $B$,the fusion process occurs at a constant temperature where the time taken is $\Delta t_B = 6.5 - 4 = 2.5 \, s$.Thus,the heat absorbed for fusion is $H_B = P 	imes \Delta t_B = 6 	imes 2.5 = 15 \, cal$.The ratio of heat absorbed is $\frac{H_A}{H_B} = \frac{24}{15} = \frac{8}{5}$.

Two substances $A$ and $B$ of equal mass $m$ are heated at a uniform rate of $6 \, cal \, s^{-1}$ under similar conditions. $A$ graph between temperature and time is shown in the figure. The ratio of heat absorbed $H_A/H_B$ by them for complete fusion is

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