Two tangent galvanometer coils of the same ra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a tangent galvanometer,the current $I$ is given by $I = K 	an 	heta$,where $K$ is the reduction factor.Since the coils are connected in seri

Vedclass · Accepted Answer

$\frac{\sqrt{3}}{1}$

Vedclass · Answer

(B) For a tangent galvanometer,the current $I$ is given by $I = K 	an 	heta$,where $K$ is the reduction factor.Since the coils are connected in series,the current $I$ is the same for both.Therefore,$K_1 	an 	heta_1 = K_2 	an 	heta_2$.Given $	heta_1 = 60^o$ and $	heta_2 = 45^o$,we have $K_1 	an 60^o = K_2 	an 45^o$.$K_1 (\sqrt{3}) = K_2 (1) \Rightarrow \frac{K_1}{K_2} = \frac{1}{\sqrt{3}}$.The reduction factor $K$ is given by $K = \frac{2 R B_H}{\mu_0 N}$,where $R$ is the radius and $N$ is the number of turns.Since $R$ is the same for both,$K \propto \frac{1}{N}$,which implies $\frac{K_1}{K_2} = \frac{N_2}{N_1}$.Thus,$\frac{N_2}{N_1} = \frac{1}{\sqrt{3}}$,which means $\frac{N_1}{N_2} = \frac{\sqrt{3}}{1}$.

Two tangent galvanometer coils of the same radius are connected in series. The current flowing produces deflections of $60^o$ and $45^o$. The ratio of the number of turns in the coils is:

Similar Questions

Before use,a vibration magnetometer should be set:

Magnetic moments of two bar magnets may be compared with the help of

Two tangent galvanometer coils of the same radius are connected in series. The current flowing produces deflections of $60^o$ and $45^o$. The ratio of the number of turns in the coils is:

$A$ magnetic needle is made to vibrate in a uniform magnetic field $H$. Its time period is $T$. If it vibrates in a field of intensity $4H$,its time period will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module