Two tangents are drawn from the point $P(-1, 1)$ to the circle $x^{2}+y^{2}-2x-6y+6=0$. If these tangents touch the circle at points $A$ and $B$,and if $D$ is a point on the circle such that the lengths of the segments $AB$ and $AD$ are equal,then the area of the triangle $ABD$ is equal to:

  • A
    $2$
  • B
    $(3\sqrt{2}+2)$
  • C
    $4$
  • D
    $3(\sqrt{2}-1)$

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