Two trains of equal length are running on par | vedclass

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(A) Let the length of each train be $l$ meters.Total length to be covered by the faster train to pass the slower train $= l + l = 2l$ meters.Relative

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(A) Let the length of each train be $l$ meters.Total length to be covered by the faster train to pass the slower train $= l + l = 2l$ meters.Relative speed of the faster train with respect to the slower train $= 46 - 36 = 10 \; km/h$.Convert the relative speed into $m/s$: $10 	imes \frac{5}{18} = \frac{50}{18} = \frac{25}{9} \; m/s$.Using the formula: $	ext{Relative Speed} = \frac{	ext{Total Distance}}{	ext{Time}}$.$\frac{25}{9} = \frac{2l}{36}$.$2l = \frac{25 	imes 36}{9}$.$2l = 25 	imes 4 = 100$.$l = 50 \; m$.Thus,the length of each train is $50 \; m$.

Two trains of equal length are running on parallel tracks in the same direction at $46 \; km/h$ and $36 \; km/h$ respectively. The faster train passes the slower train in $36 \; seconds$. The length (in $m$) of each train is:

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