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(C) Speed of the first train $(S_1) = \frac{120\, m}{10\, s} = 12\, m/s$.Speed of the second train $(S_2) = \frac{120\, m}{15\, s} = 8\, m/s$.When two

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$12$

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(C) Speed of the first train $(S_1) = \frac{120\, m}{10\, s} = 12\, m/s$.Speed of the second train $(S_2) = \frac{120\, m}{15\, s} = 8\, m/s$.When two trains travel in opposite directions,their relative speed is the sum of their individual speeds: $S_{rel} = S_1 + S_2 = 12 + 8 = 20\, m/s$.The total distance to be covered to cross each other is the sum of their lengths: $D = 120\, m + 120\, m = 240\, m$.Time taken to cross each other $= \frac{	ext{Total Distance}}{	ext{Relative Speed}} = \frac{240\, m}{20\, m/s} = 12\, s$.

Two trains of equal length take $10\, seconds$ and $15\, seconds$ respectively to cross a telegraph post. If the length of each train is $120\, metres,$ in what time (in $seconds$) will they cross each other when travelling in opposite directions?

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