(D) Given, frequencies of tuning forks $X$ and $Y$ are:$n_X = 280 \,Hz$$n_Y = 284 \,Hz$Let the frequency of tuning fork $Z$ be $n_Z$ and the beat freq

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(D) Given, frequencies of tuning forks $X$ and $Y$ are:$n_X = 280 \,Hz$$n_Y = 284 \,Hz$Let the frequency of tuning fork $Z$ be $n_Z$ and the beat frequency produced by $X$ and $Z$ be $b$.From the first condition, $b = |n_Z - 280|$.From the second condition, the beat frequency produced by $Y$ and $Z$ is $3b$, so $3b = |n_Z - 284|$.Case $1$: If $n_Z > 284$, then $n_Z - 280 = b$ and $n_Z - 284 = 3b$. Substituting $b$, we get $n_Z - 284 = 3(n_Z - 280) \Rightarrow n_Z - 284 = 3n_Z - 840 \Rightarrow 2n_Z = 556 \Rightarrow n_Z = 278 \,Hz$. This contradicts $n_Z > 284$.Case $2$: If $n_Z Thus, the frequency of $Z$ is $278 \,Hz$.

Class 11 Physics Waves and Sound Beats and Tuning fork

Difficult

Two tuning forks $X$ and $Y$ have frequencies $280 \,Hz$ and $284 \,Hz$. $A$ third tuning fork $Z$ has an unknown frequency. When $X$ and $Z$ are sounded together, a certain number of beats per second are heard. When $Y$ and $Z$ are sounded together, the beat frequency is found to be three times as great. The frequency of $Z$ is: (in $\,Hz$)

AP EAMCET 2020 All AP EAMCET

A
$282$
B
$286$
C
$280$
D
$278$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

Waves and Sound

Subtopic

Beats and Tuning fork

Previous Year

AP EAMCET 2020 Paper All AP EAMCET years →

$A$ wire vibrates at a fundamental frequency of $500 \,Hz$. $A$ second identical wire produces $5$ beats per second with it when the tension in the first wire is slightly decreased. The ratio of the tension in the second wire to the tension in the first wire is approximately equal to

EasyTS EAMCET 2021

View Solution

$A$ source of frequency $\nu$ gives $5$ beats/second when sounded with a source of frequency $200 \;Hz$. The second harmonic of frequency $2\nu$ of the source gives $10$ beats/second when sounded with a source of frequency $420 \;Hz$. The value of $\nu$ is .... $Hz$.

MediumAIPMT 1994

View Solution

When a tuning fork of frequency $341 \ Hz$ is sounded with another tuning fork,six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork,the number of beats is two per second. The natural frequency of the second tuning fork is: (in $Hz$)

Medium

View Solution

$A$ tuning fork arrangement (pair) produces $4 \, beats/sec$ with one fork of frequency $288 \, cps$. $A$ little wax is placed on the unknown fork and it then produces $2 \, beats/sec$. The frequency of the unknown fork is .... $cps$.

MediumAIEEE 2002

View Solution

When an air column at $15 ^\circ C$ and a tuning fork are sounded together, $4$ beats per second are produced. The frequency of the fork is less than that of the air column. When the temperature falls to $10 ^\circ C$, the beat frequency decreases by one. The frequency of the fork will be ..... $Hz$ $[V_{sound}$ at $0 ^\circ C = 332, m/s]$.

Difficult

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Similar Questions

$A$ wire vibrates at a fundamental frequency of $500 \,Hz$. $A$ second identical wire produces $5$ beats per second with it when the tension in the first wire is slightly decreased. The ratio of the tension in the second wire to the tension in the first wire is approximately equal to

$A$ source of frequency $\nu$ gives $5$ beats/second when sounded with a source of frequency $200 \;Hz$. The second harmonic of frequency $2\nu$ of the source gives $10$ beats/second when sounded with a source of frequency $420 \;Hz$. The value of $\nu$ is .... $Hz$.

When a tuning fork of frequency $341 \ Hz$ is sounded with another tuning fork,six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork,the number of beats is two per second. The natural frequency of the second tuning fork is: (in $Hz$)

$A$ tuning fork arrangement (pair) produces $4 \, beats/sec$ with one fork of frequency $288 \, cps$. $A$ little wax is placed on the unknown fork and it then produces $2 \, beats/sec$. The frequency of the unknown fork is .... $cps$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module