Two tuning forks of frequencies $256$ and $258$ vibrations/sec are sounded together,then the time interval between consecutive maxima heard by the observer is ..... $sec$.

Two strings $X$ and $Y$ of a sitar produce a beat frequency of $4 \ Hz$. When the tension of the string $Y$ is slightly increased,the beat frequency is found to be $2 \ Hz$. If the frequency of $X$ is $300 \ Hz$,then the original frequency of $Y$ was .... $Hz$.

Ten tuning forks are arranged in increasing order of frequency in such a way that any two nearest tuning forks produce $4 \text{ beats/sec}$. The highest frequency is twice the lowest. The possible highest and lowest frequencies are:

$41$ tuning forks are arranged in such a way that each produces $5 \text{ beats per second}$ when sounded with its nearest fork. If the frequency of the last fork is double the frequency of the first fork,then the frequencies of the first and last fork are respectively:

Two identical wires have the same fundamental frequency of $400 \text{ Hz}$ when kept under the same tension. If the tension in one wire is increased by $2\%$,the number of beats produced will be

$A$ tuning fork gives $3$ beats with $50 \ cm$ length of sonometer wire. If the length of the wire is shortened by $1 \ cm$,the number of beats is still the same. The frequency of the fork is (in $Hz$)