Two vertical poles of equal heights are 120 , | vedclass

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(B) Let the height of each pole be $h \, m$. Let the positions of the two poles be $P_1$ and $P_2$. The distance between the poles is $120 \, m$.Let $

Vedclass · Accepted Answer

$45$

Vedclass · Answer

(B) Let the height of each pole be $h \, m$. Let the positions of the two poles be $P_1$ and $P_2$. The distance between the poles is $120 \, m$.Let $A$ and $B$ be points on the line joining the bottoms of the poles such that $AB = 30 \, m$.From the geometry of the problem,the distance from the base of the first pole to $A$ is $h$ (since $	an 45^\circ = \frac{h}{dist} = 1$).Similarly,the distance from the base of the second pole to $B$ is $h$.The total distance between the poles is the sum of the distance from the first pole to $A$,the distance $AB$,and the distance from $B$ to the second pole.Therefore,$h + 30 + h = 120$.$2h = 120 - 30 = 90$.$h = 45 \, m$.

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