Two vibrating tuning forks produce progressive waves given by $Y_1 = 4\sin(500\pi t)$ and $Y_2 = 2\sin(506\pi t)$. The number of beats produced per minute is:

The wavelengths of two sound notes in air are $\frac{40}{195} \,m$ and $\frac{40}{193} \,m$. Each note produces $9$ beats per second separately with a third note of fixed frequency. The velocity of sound in air in $m/s$ is

$41$ tuning forks are arranged in increasing order of frequency. Each tuning fork produces $5 \, \text{beats/sec}$ with the next one. If the frequency of the last tuning fork is double that of the first, what are the frequencies of the first and last tuning forks?

$A$ wave has simple harmonic motion whose period is $4\; s$,while another wave which also possesses simple harmonic motion has its period $3\; s$. If both are combined,then the resultant wave will have the period equal to ....... $s$.

If two waves of the same amplitude,having frequencies $340 \ Hz$ and $335 \ Hz$,are moving in the same direction,then the time interval between two successive maxima formed (in seconds) is:

$16$ tuning forks are arranged in the order of increasing frequencies. Any two successive forks give $8$ beats per second when sounded together. If the frequency of the last fork is twice the first,then the frequency of the first fork is: