Two waves having intensity I and 9I produce i | vedclass

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(D) The resultant intensity $I_R$ of two interfering waves with intensities $I_1$ and $I_2$ and phase difference $\phi$ is given by the formula:$I_R =

Vedclass · Accepted Answer

$120$

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(D) The resultant intensity $I_R$ of two interfering waves with intensities $I_1$ and $I_2$ and phase difference $\phi$ is given by the formula:$I_R = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$Given $I_1 = I$,$I_2 = 9I$,and $I_R = 7I$,substitute these values into the equation:$7I = I + 9I + 2\sqrt{I \cdot 9I} \cos \phi$Simplify the equation:$7I = 10I + 2(3I) \cos \phi$$7I = 10I + 6I \cos \phi$Subtract $10I$ from both sides:$-3I = 6I \cos \phi$Divide by $6I$:$\cos \phi = -\frac{3I}{6I} = -\frac{1}{2}$Since $\cos \phi = -\frac{1}{2}$,the phase difference $\phi$ is $120^{\circ}$.

$x$	$1$	$2$	$3$	$4$
$y$	$0.7111$	$0.7222$	$0.7333$	$0.7444$

Two waves having intensity $I$ and $9I$ produce interference. If the resultant intensity at a point is $7I$,the phase difference between the two waves is.....$^o$

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