Two waves of intensity I undergo interference | vedclass

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(D) The resultant intensity $I_R$ of two interfering waves with intensities $I_1$ and $I_2$ is given by the formula:$I_R = I_1 + I_2 + 2\sqrt{I_1 I_2}

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$4I$

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(D) The resultant intensity $I_R$ of two interfering waves with intensities $I_1$ and $I_2$ is given by the formula:$I_R = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$where $\phi$ is the phase difference between the waves.For maximum intensity,the phase difference $\phi$ must be $0^\circ$ (or an even multiple of $\pi$),which makes $\cos \phi = 1$.Given $I_1 = I$ and $I_2 = I$,we substitute these values into the formula:$I_{max} = I + I + 2\sqrt{I \cdot I} \cos 0^\circ$$I_{max} = 2I + 2\sqrt{I^2} (1)$$I_{max} = 2I + 2I = 4I$Therefore,the maximum intensity obtained is $4I$.

Two waves of intensity $I$ undergo interference. The maximum intensity obtained is

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