Two weights 2 ,N and 3 ,N are suspended from | vedclass

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(C) Let the weights be $W_1 = 2 \,N$ and $W_2 = 3 \,N$. The masses are $m_1 = W_1/g$ and $m_2 = W_2/g$.The pulley is accelerated upwards with $a = g$.

Vedclass · Accepted Answer

$4.8$

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(C) Let the weights be $W_1 = 2 \,N$ and $W_2 = 3 \,N$. The masses are $m_1 = W_1/g$ and $m_2 = W_2/g$.The pulley is accelerated upwards with $a = g$.In the frame of the pulley, each mass experiences a pseudo-force $F_p = ma$ acting downwards.Thus, the effective acceleration due to gravity for each mass becomes $g_{eff} = g + a = g + g = 2g$.The effective weights are $W_1' = m_1(2g) = 2W_1 = 4 \,N$ and $W_2' = m_2(2g) = 2W_2 = 6 \,N$.The tension $T$ in a string over a pulley with masses $m_1$ and $m_2$ is given by $T = \frac{2m_1m_2}{m_1+m_2} g_{eff}$.Substituting the effective weights: $T = \frac{2 W_1' W_2'}{W_1' + W_2'} = \frac{2 	imes 4 	imes 6}{4 + 6} = \frac{48}{10} = 4.8 \,N$.

Two weights $2 \,N$ and $3 \,N$ are suspended from the ends of an inextensible string passing over a fixed frictionless pulley. If the pulley is pulled up with an acceleration equal to the acceleration due to gravity $(g)$, then the tension in the string is: (in $\,N$)

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