Two wires have resistances of 2 Omega and 4 | vedclass

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(C) The heat dissipated $H$ in a resistor is given by the formula $H = \frac{V^2}{R} t$,where $V$ is the voltage,$R$ is the resistance,and $t$ is the

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$2:1$

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(C) The heat dissipated $H$ in a resistor is given by the formula $H = \frac{V^2}{R} t$,where $V$ is the voltage,$R$ is the resistance,and $t$ is the time.Since the voltage $V$ and time $t$ are the same for both wires,the heat dissipated is inversely proportional to the resistance: $H \propto \frac{1}{R}$.Therefore,the ratio of heat dissipated is $\frac{H_1}{H_2} = \frac{R_2}{R_1}$.Given $R_1 = 2 \ \Omega$ and $R_2 = 4 \ \Omega$,we have $\frac{H_1}{H_2} = \frac{4}{2} = \frac{2}{1}$.Thus,the ratio is $2:1$.

Two wires have resistances of $2 \ \Omega$ and $4 \ \Omega$ and are connected to the same voltage. The ratio of heat dissipated in the resistances is:

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