Two wooden blocks of masses M and m are place | vedclass

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(A) Let the acceleration of the system be $a$ towards the right.For the block of mass $m$ to remain stationary with respect to the block of mass $M$,t

Vedclass · Accepted Answer

$(M+m) g 	an \beta$

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(A) Let the acceleration of the system be $a$ towards the right.For the block of mass $m$ to remain stationary with respect to the block of mass $M$,the pseudo force $ma$ acting on $m$ must balance the component of gravity along the incline.In the frame of the block $M$,the forces acting on $m$ are:$1$. Gravity $mg$ acting downwards.$2$. Normal force $N$ perpendicular to the incline.$3$. Pseudo force $ma$ acting horizontally to the left.Resolving the forces along the incline,for equilibrium:$ma \cos \beta = mg \sin \beta$$a = g \frac{\sin \beta}{\cos \beta} = g 	an \beta$Now,considering the whole system of mass $(M+m)$ moving with acceleration $a$ under the force $P$:$P = (M+m) a$Substituting the value of $a$:$P = (M+m) g 	an \beta$

Two wooden blocks of masses $M$ and $m$ are placed on a smooth horizontal surface as shown in the figure. If a force $P$ is applied to the system as shown in the figure such that the mass $m$ remains stationary with respect to the block of mass $M$,then the magnitude of the force $P$ is

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