Two years ago,the value of a motorbike was ₹ | vedclass

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(B) The formula for depreciation is $A = P(1 - \frac{R}{100})^T$,where $P$ is the initial value,$R$ is the rate of depreciation,and $T$ is the time in

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$57600$

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(B) The formula for depreciation is $A = P(1 - \frac{R}{100})^T$,where $P$ is the initial value,$R$ is the rate of depreciation,and $T$ is the time in years.Given: $P = 62500$,$R = 4 \%$,$T = 2$ years.Substituting the values:$A = 62500(1 - \frac{4}{100})^2$$A = 62500(1 - \frac{1}{25})^2$$A = 62500(\frac{24}{25})^2$$A = 62500 	imes \frac{576}{625}$$A = 100 	imes 576 = 57600$.Therefore,the current value of the motorbike is $₹ 57600$.

Two years ago,the value of a motorbike was $₹ 62,500$. If the value depreciates by $4 \%$ every year,what is its value now?

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