Under isothermal condition,a gas at 300 ; K e | vedclass

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Question

(A) The work done during expansion against a constant external pressure is given by the formula:$W = -P_{ext} 	imes \Delta V$Given:$P_{ext} = 2 \; ba

Vedclass · Accepted Answer

$-30 \; J$

Vedclass · Answer

(A) The work done during expansion against a constant external pressure is given by the formula:$W = -P_{ext} 	imes \Delta V$Given:$P_{ext} = 2 \; bar$$V_{1} = 0.1 \; L$$V_{2} = 0.25 \; L$Change in volume:$\Delta V = V_{2} - V_{1} = 0.25 \; L - 0.1 \; L = 0.15 \; L$Calculating work done:$W = -2 \; bar 	imes 0.15 \; L = -0.30 \; bar \cdot L$Since $1 \; L \cdot bar = 100 \; J$:$W = -0.30 	imes 100 \; J = -30 \; J$The work done by the gas is $-30 \; J$.

Under isothermal condition,a gas at $300 \; K$ expands from $0.1 \; L$ to $0.25 \; L$ against a constant external pressure of $2 \; bar$. The work done by the gas is .... [Given that $1 \; L \; bar = 100 \; J$]

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