Upon mixing equal volumes of aqueous solution | vedclass

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Question

(B) The correct option is $B$.Let the volume of both $HCl$ and $H_2SO_4$ solutions be $V$.Number of moles of $H^{+}$ ions from $HCl = 	ext{Molarity}

Vedclass · Accepted Answer

$0.25$

Vedclass · Answer

(B) The correct option is $B$.Let the volume of both $HCl$ and $H_2SO_4$ solutions be $V$.Number of moles of $H^{+}$ ions from $HCl = 	ext{Molarity} 	imes 	ext{Basicity} 	imes 	ext{Volume} = 0.1 	imes 1 	imes V = 0.1 \, V$.Number of moles of $H^{+}$ ions from $H_2SO_4 = 0.2 	imes 2 	imes V = 0.4 \, V$.Total moles of $H^{+}$ ions in the mixture $= 0.1 \, V + 0.4 \, V = 0.5 \, V$.Total volume of the resulting solution $= V + V = 2 \, V$.Concentration of $H^{+}$ ions $[H^{+}] = \frac{	ext{Total moles of } H^{+}}{	ext{Total volume}} = \frac{0.5 \, V}{2 \, V} = 0.25 \, mol / L$.

Upon mixing equal volumes of aqueous solutions of $0.1 \, M \, HCl$ and $0.2 \, M \, H_2SO_4$,the concentration of $H^{+}$ in the resulting solution is $.... \, mol / L$.

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