Using $s, p, d, f$ notations,describe the orbital with the following quantum numbers:
$(a) n=2, l=1$
$(b) n=4, l=0$
$(c) n=5, l=3$
$(d) n=3, l=2$

The number of orbitals in $2p$ sub-shell is

According to which principle is the electronic configuration of nitrogen $1s^2 2s^2 2p_x^1 2p_y^1 2p_z^1$ and not $1s^2 2s^2 2p_x^2 2p_y^1 2p_z^0$?

How many electrons in an atom can have the following quantum numbers?
$(a)$ $n = 4, m_s = -\frac{1}{2}$
$(b)$ $n = 3, l = 0$

The number of valence electrons in an atom with electronic configuration $1s^2 2s^2 2p^6 3s^2 3p^3$ is

Given below are two statements:
Statement-$I$: The orbitals having same energy are called as degenerate orbitals.
Statement-$II$: In hydrogen atom,$3p$ and $3d$ orbitals are not degenerate orbitals.
In the light of the above statements,choose the most appropriate answer from the options given.