To represent compounds using Stock notation,we determine the oxidation state of the metal and write it in Roman numerals in parentheses after the metal symbol.
$1$. $HAuCl_{4}$: Oxidation state of $Au$ is $+3$,so it is $HAu(III)Cl_{4}$.
$2$. $Tl_{2}O$: Oxidation state of $Tl$ is $+1$,so it is $Tl_{2}(I)O$.
$3$. $FeO$: Oxidation state of $Fe$ is $+2$,so it is $Fe(II)O$.
$4$. $Fe_{2}O_{3}$: Oxidation state of $Fe$ is $+3$,so it is $Fe_{2}(III)O_{3}$.
$5$. $CuI$: Oxidation state of $Cu$ is $+1$,so it is $Cu(I)I$.
$6$. $CuO$: Oxidation state of $Cu$ is $+2$,so it is $Cu(II)O$.
$7$. $MnO$: Oxidation state of $Mn$ is $+2$,so it is $Mn(II)O$.
$8$. $MnO_{2}$: Oxidation state of $Mn$ is $+4$,so it is $Mn(IV)O_{2}$.